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Differentiate between mechanical stopwatches and digital stopwatches.

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Physics Class 9 (SSC-1),  Conceptual Question No.5  Unit-1: Physical Quantities and Measurement  (National Book Foundation as Federal Text Book, Islamabad) Q.   Differentiate between mechanical stopwatches and digital stopwatches.   Answer: MECHANICAL/ANALOGUE STOPWATCH: A mechanical stopwatch  can measure a time interval of up to 0.1 seconds.  It has a knob that is  used to wind the spring that powers the watch.  It can also be used as a start stop and reset button. It has two circular dials, a large circular dial in which the second hand of the watch rotates, and a small circular dial in which the minute hand of the watch rotates as shown in the figure. The watch starts and stops by pressing the knob at top of it, pressing it for some time will reset the watch back to zero. DIGITAL STOPWATCH: A digital stopwatch can measure a time interval of up to 0.01 seconds. The digital stopwatch is usually controlled by two ...

Screw gauge can give a more precise length than vernier callipers. Briefly explain why?

Physics Class 9 (SSC-1),  Conceptual Question No.4  Unit-1: Physical Quantities and Measurement  (National Book Foundation as Federal Text Book, Islamabad) Q.     Screw gauge can give a more precise length than vernier calipers. Briefly explain why?   Answer: The  Vernier Caliper   is a precision instrument that can be used to measure internal and external distance/length extremely accurately. While  Micrometer screw gauge  is also a  distance/length  measuring instrument used for measuring  extremely small dimensions and is  extensively used in the engineering  field for obtaining precision measurements.  The screw gauge is more precise than Vernier calipers because the least count of Vernier calipers is 0.1 mm and for the screw gauge, it is 0.01 mm. So, a screw gauge can measure more precisely than a Vernier caliper.  Related Questions: Q.1   Physics has made our live comfo...

Show that the prefix micro is a thousand times greater than the prefix nano - Physics Class 9 (SSC-1)

Physics Class 9 (SSC-1),  Conceptual Question No.3  Unit-1: Physical Quantities and Measurement  (National Book Foundation as Federal Text Book, Islamabad) Q.   Show that the prefix micro is a thousand times greater than the prefix nano.   Answer: We know that 1 micro (µ)  = 10 ⁻ ⁶ ----------(1) and 1 nano (n)  = 10 ⁻ ⁹  ------------(2) In order to get the desire relation b/w micro (10 ⁻ ⁶) and nano  ( 10 ⁻⁹) , We will multiply the Eqn (1) R.H.S. by  10 ⁻ ³  x  10³ 1 micro (µ)  =  10 ⁻ ⁶ x  10 ⁻ ³   x  10³    [ ∴  10 ⁻ ³  x  10⁺³  =  1] 1 micro (µ)  =  10 ⁻ ⁶ ⁻ ³  x  10³ 1 micro (µ)  =  10 ⁻⁹  x  10³ 1 micro (µ)  =   10³ x  10 ⁻⁹ 1 micro (µ)  =   10³ nano (n)         ( ∴  10 ⁻ ⁹  =  n ) or 1 micro (µ) =  1000  nano (n) This show...

Best Speech on Pakistan day (23rd March) Speech in English - The Pakistan Resolution Day

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Please Subscribe to the YouTube channel 👆👆👆 23rd March ( Pakistan Day ) Speech on YouTube 👆👆👆 Respected Principal, Honorable Teachers, and My Dear Fellow Students, Assalamu Alaikum! Today, we have gathered here to celebrate 23rd March, a day of great historical significance for our beloved country, Pakistan. It is a day that reminds us of the struggles, sacrifices, and dreams of our forefathers who envisioned a separate homeland where we could live with dignity, freedom, and harmony. Dear fellows!  On 23rd March 1940, the Lahore Resolution, also known as the Pakistan Resolution, was passed at Minto Park (now Iqbal Park) in Lahore. Under the leadership of Quaid-e-Azam Muhammad Ali Jinnah, the All India Muslim League declared its demand for an independent state for the Muslims of the Indian subcontinent. This resolution became the foundation stone for the creation of Pakistan, which finally emerged as an independent nation on 14th August 1947. Worthily guests! Pakistan Day is...

What base quantities are involved in these derived physical quantities; force, pressure, power, and charge.

Physics Class 9 (SSC-1),  Conceptual Question No.2  Unit-1: Physical Quantities and Measurement  (National Book Foundation as Federal Text Book, Islamabad) Q. What base quantities are involved in these derived physical quantities; force, pressure, power, and charge.  Answer: (a)  Force: Force F =  m a SI Unit of force is Newton (N) =  kg   m s⁻² Base quantities involved in force are  mass, length, and time. (b)  Pressure Pressure = force / area Pressure =  F  /  A The SI unit of force (F=ma) is Newton N =  kg   m s⁻² and the unit of area A is m ²   The SI Unit of Pressure is Pascal "Pa" =  kg   m s⁻² /  m ² =  kg   m⁻¹ s⁻² So, the Base quantities involved in Pressure are  Mass ,  length, and time. (c)  Power Power = work / time Power =  W  /  t The SI unit of Work (W=F.d) is joule (J) =  kg   m ²  s⁻² and unit of time is secon...

Q. Physics has made our lives comfortable. Justify this statement. Physics Class 9 (SSC-1)

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Physics Class 9 (SSC-1),  Conceptual Question No.1  Unit-1: Physical Quantities and Measurement  (National Book Foundation as Federal Text Book, Islamabad) Q. Physics has made our lives comfortable. " justify this statement.  Answer: Physics has made our lives comfortable in a lot of ways. The technological devices that we use on a regular basis like electrical appliances, computers, smartphones, the internet, etc., and the technological devices about which we heard like rockets and space shuttles, magnetically levitating trains, and microscopic robots that fight cancer cells in our bodies, are all based on the principles of physics. Further research in physics helps to develop the consumer goods that we use at home, thereby improving our standard of living. The invention or discoveries in physics has made our lives dependent and we no longer can imagine our lives without technologies discovered or invented based on the principles of physics. ...

Derivation of equations of motion graphically for uniformly accelerated rectilinear motion

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Derivation of equations of motion graphically for uniformly accelerated rectilinear motion  There are three basic equations of motion for bodies having uniformly accelerated rectilinear motion. These three equations relate time t , distance covered S , initial velocity  `\ v_i` , final velocity  `\ v_f`,  and acceleration an of a moving body. To simplify the derivation of these equations, we assume that: The motion of the body is rectilinear motion (motion in a straight line). The body is moving with uniform acceleration and Assuming only the magnitude of displacements, velocities, and acceleration. Consider a body moving with initial velocity `\ v_i` in a straight line with uniform acceleration a . Its velocity becomes  `\ v_f`  after time t . The motion of the body is described by a speed-time graph as shown in the figure by line AB . The slope of line AB is acceleration a . The total distance covered by the body is shown by the shaded area und...