Physics Formula Sheet – Electrostatics | Class 12 Notes

Physics Formula Sheet – Chapter 11: Electrostatics

Preparing for Board Examinations, MDCAT, ECAT, NUST, PIEAS, GIKI, UET, FAST, or other competitive entrance tests? This Electrostatics Formula Sheet brings together all the important formulas from Chapter 11 in one organized place.

Instead of searching through lengthy notes, students can quickly revise every important equation related to Electric Charge, Coulomb's Law, Electric Field, Electric Dipole, Gauss's Law, Electric Potential, Potential Difference, Equipotential Surfaces, Capacitance, and Capacitors. Each formula is presented in a clear and student-friendly format, making revision faster and more effective.

Whether you are revising before an examination, solving numerical problems, or preparing for competitive tests, this formula sheet serves as a quick reference guide. It also helps students understand the relationship between different concepts, making problem-solving easier and improving conceptual learning.

At Physics Learning Hub, our goal is to provide comprehensive, syllabus-based, and exam-oriented study material that supports students at every level. Along with this formula sheet, you can also explore detailed chapter notes, solved numericals, derivations, MCQs, conceptual questions, and revision resources designed according to modern learning outcomes (SLOs).

Complete Formula Sheet

Electrostatic Force

$F=\frac{1}{4\pi\varepsilon_0}\frac{q_1q_2}{r^2}$

Electric Field

$E=\frac{F}{q}$ $E=\frac{1}{4\pi\varepsilon_0}\frac{Q}{r^2}$

Electric Dipole Moment

$p=qd$

Electric Field Due to Dipole

Axial Position

$E=\frac{1}{4\pi\varepsilon_0}\frac{2p}{r^3}$

Equatorial Position

$E=\frac{1}{4\pi\varepsilon_0}\frac{p}{r^3}$

Torque on Dipole

$\tau=pE\sin\theta$

Potential Energy of Dipole

$U=-pE\cos\theta$

Electric Flux

$\Phi=EA\cos\theta$

Gauss's Law

$\oint\vec E\cdot d\vec A=\frac{Q}{\varepsilon_0}$

Electric Potential

$V=\frac{W}{q}$ $V=\frac{1}{4\pi\varepsilon_0}\frac{Q}{r}$

Potential Difference

$\Delta V=\frac{W}{q}$ $\Delta V=Ed$

Electric Field and Potential

$E=-\frac{dV}{dr}$

Capacitance

$C=\frac{Q}{V}$

Parallel Plate Capacitor

$C=\frac{\varepsilon_0A}{d}$

Capacitor with Dielectric

$C=K\frac{\varepsilon_0A}{d}$

Energy Stored

$U=\frac12CV^2$ $U=\frac12QV$ $U=\frac{Q^2}{2C}$

Capacitors in Series

$\frac1C=\frac1{C_1}+\frac1{C_2}+\cdots$

Capacitors in Parallel

$C=C_1+C_2+\cdots$

🎯 Continue Your Preparation

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📚 Physics Learning Hub 📚 Physics MCQs Hub 🧮 Electrostatics Notes 📐 Solved Numerical

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