Current & Electricity – 100 Advanced & Numerical with Answers & Explanations | Board & MDCAT Preparation

Current & Electricity – 100 Advanced & Numerical with Answers & Explanations | Board & MDCAT Preparation

100 Advanced & Numerical MCQs (Level -2) on Current & Electricity, Physics (Unit-Wise MCQs Practice):



Whether you are preparing for board examinations, chapter tests, college assessments, or competitive entrance exams (MDCAT, ECAT, NUST, PIEAS, GIKI, UET, FAST, and other engineering or medical admission tests), this comprehensive MCQ collection is designed to help you master Current & Electricity. The questions are arranged progressively—from basic concepts to advanced numerical problems and higher-order thinking—ensuring complete and systematic preparation for every type of examination.

This chapter-wise MCQ collection includes:

This MCQ collection covers:

  • Steady current and drift velocity
  • Ohm's law and electrical resistance
  • Resistivity, conductivity, and conductance
  • Temperature effects on resistance and resistivity
  • Variable resistors, thermistors, and potential divider
  • Electromotive force (EMF) and internal resistance
  • Electric power and maximum power transfer
  • Thermocouples and resistance thermometers
  • Kirchhoff's Current Law (KCL) and Voltage Law (KVL)
  • Wheatstone bridge and potentiometer

Every MCQ includes the correct answer with a clear, concept-based explanation to strengthen understanding, improve numerical ability, and reinforce key physics concepts.

This question bank helps students to:

  • Build strong conceptual understanding
  • Improve numerical and analytical skills
  • Master electrical circuits and network analysis
  • Strengthen problem-solving techniques
  • Avoid common examination mistakes
  • Increase speed, accuracy, and confidence
  • Prepare effectively for both board and competitive examinations

With 250 carefully selected MCQs arranged into 100 Basic, 100 Advanced & Numerical, and 50 HOTS questions, along with 50 Challenging Quiz MCQs, this all-in-one Current & Electricity MCQ Bank provides complete preparation for examinations and competitive entrance tests while helping students achieve maximum scores.


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Current & Electricity (Level 2) – – 100 Advanced & Numerical MCQs (MCQs 101–200)


MCQ No. 101

A current of 5 A flows through a conductor for 4 minutes. The total charge passing through the conductor is:

a. 300 C
b. 600 C
c. 1200 C
d. 1500 C

Correct answer: c. 1200 C

Explanation:
Using Q=ItQ = It:

Q=5×(4×60)=1200  CQ = 5 \times (4 \times 60)=1200\;C

MCQ No. 102

A resistor of 20 Ω is connected across a 100 V supply. The current through the resistor is:

a. 2 A
b. 4 A
c. 5 A
d. 10 A

Correct answer: c. 5 A

Explanation:
Using Ohm's law,

I=VR=10020=5AI=\frac{V}{R}=\frac{100}{20}=5A

MCQ No. 103

A conductor carries 3 A of current for 5 minutes. The number of coulombs passing through the conductor is:

a. 300 C
b. 600 C
c. 900 C
d. 1200 C

Correct answer: c. 900 C

Explanation:

Q=It=3×300=900  CQ=It=3\times300=900\;C

MCQ No. 104

A resistor draws 2 A from a 12 V battery. Its resistance is:

a. 3 Ω
b. 4 Ω
c. 6 Ω
d. 24 Ω

Correct answer: c. 6 Ω

Explanation:

R=VI=122=6  ΩR=\frac{V}{I}=\frac{12}{2}=6\;\Omega

MCQ No. 105

A wire has a resistance of 15 Ω. If the current through it is 4 A, the potential difference across it is:

a. 45 V
b. 50 V
c. 60 V
d. 75 V

Correct answer: c. 60 V

Explanation:

V=IR=4×15=60VV=IR=4\times15=60V

MCQ No. 106

Two resistors of 6 Ω and 3 Ω are connected in series. Their equivalent resistance is:

a. 2 Ω
b. 6 Ω
c. 9 Ω
d. 18 Ω

Correct answer: c. 9 Ω

Explanation:
For series combination,

Req=6+3=9  ΩR_{eq}=6+3=9\;\Omega

MCQ No. 107

Two resistors of 6 Ω and 3 Ω are connected in parallel. Their equivalent resistance is:

a. 2 Ω
b. 3 Ω
c. 4 Ω
d. 9 Ω

Correct answer: a. 2 Ω

Explanation:

1R=16+13=12\frac1R=\frac16+\frac13=\frac12

Hence,

R=2  ΩR=2\;\Omega

MCQ No. 108

The power consumed by a 10 Ω resistor carrying 2 A current is:

a. 20 W
b. 30 W
c. 40 W
d. 80 W

Correct answer: c. 40 W

Explanation:

P=I2R=(2)2×10=40WP=I^2R=(2)^2\times10=40W

MCQ No. 109

A 220 V, 100 W lamp draws a current of:

a. 0.23 A
b. 0.45 A
c. 1.0 A
d. 2.2 A

Correct answer: b. 0.45 A

Explanation:

I=PV=100220=0.45AI=\frac{P}{V}=\frac{100}{220}=0.45A

MCQ No. 110

A 200 W appliance operates for 3 hours. The electrical energy consumed is:

a. 0.2 kWh
b. 0.4 kWh
c. 0.6 kWh
d. 6.0 kWh

Correct answer: c. 0.6 kWh

Explanation:

Energy=0.2×3=0.6  kWhEnergy=0.2\times3=0.6\;kWh

MCQ No. 111

A conductor has resistance 8 Ω. If the applied voltage is doubled, the current becomes:

a. Half
b. Double
c. Four times
d. Unchanged

Correct answer: b. Double

Explanation:
Since resistance remains constant,

IVI\propto V

MCQ No. 112

A battery delivers 24 J of energy while moving 4 C of charge. Its e.m.f. is:

a. 4 V
b. 5 V
c. 6 V
d. 8 V

Correct answer: c. 6 V

Explanation:

ε=WQ=244=6V\varepsilon=\frac{W}{Q}=\frac{24}{4}=6V

MCQ No. 113

The resistance of a wire becomes four times its original value when:

a. Length becomes half
b. Radius becomes double
c. Length doubles while area halves
d. Temperature decreases

Correct answer: c. Length doubles while area halves

Explanation:
Since

R=ρLAR=\rho\frac{L}{A}

doubling length and halving area makes resistance four times.


MCQ No. 114

A 12 Ω resistor carries 3 A current. The electrical power developed is:

a. 36 W
b. 72 W
c. 96 W
d. 108 W

Correct answer: d. 108 W

Explanation:

P=I2R=9×12=108WP=I^2R=9\times12=108W

MCQ No. 115

A 60 W bulb operates on 120 V. Its resistance is:

a. 120 Ω
b. 180 Ω
c. 240 Ω
d. 360 Ω

Correct answer: c. 240 Ω

Explanation:

R=V2P=120260=240ΩR=\frac{V^2}{P}=\frac{120^2}{60}=240\Omega

MCQ No. 116

The equivalent resistance of 4 Ω and 12 Ω connected in parallel is:

a. 2 Ω
b. 3 Ω
c. 4 Ω
d. 16 Ω

Correct answer: b. 3 Ω

Explanation:

R=4×124+12=4816=3ΩR=\frac{4\times12}{4+12}=\frac{48}{16}=3\Omega

MCQ No. 117

A current of 0.5 A flows for 20 s. The charge transferred is:

a. 5 C
b. 10 C
c. 15 C
d. 20 C

Correct answer: b. 10 C

Explanation:

Q=It=0.5×20=10CQ=It=0.5\times20=10C

MCQ No. 118

An electric heater rated 1000 W operates for 30 minutes. Energy consumed is:

a. 0.25 kWh
b. 0.50 kWh
c. 1.00 kWh
d. 1.50 kWh

Correct answer: b. 0.50 kWh

Explanation:

Energy=1×0.5=0.5kWhEnergy=1\times0.5=0.5kWh

MCQ No. 119

If a cell has an e.m.f. of 2.0 V and internal resistance 0.2 Ω, supplying 2 A, its terminal voltage is:

a. 1.2 V
b. 1.4 V
c. 1.6 V
d. 2.0 V

Correct answer: c. 1.6 V

Explanation:

V=εIr=2(2×0.2)=1.6VV=\varepsilon-Ir=2-(2\times0.2)=1.6V

MCQ No. 120

A resistor of 50 Ω is connected across 200 V. The power dissipated is:

a. 200 W
b. 400 W
c. 600 W
d. 800 W

Correct answer: d. 800 W

Explanation:

P=V2R=200250=800WP=\frac{V^2}{R}=\frac{200^2}{50}=800W

MCQ No. 121

The resistance of a wire is 8 Ω. When cut into four equal pieces, the resistance of each piece becomes:

a. 8 Ω
b. 4 Ω
c. 2 Ω
d. 0.5 Ω

Correct answer: c. 2 Ω

Explanation:
Resistance is directly proportional to length. One-fourth the length gives one-fourth the resistance.


MCQ No. 122

Three resistors of 2 Ω, 3 Ω, and 5 Ω are connected in series. Their equivalent resistance is:

a. 5 Ω
b. 8 Ω
c. 10 Ω
d. 30 Ω

Correct answer: c. 10 Ω

Explanation:

Req=2+3+5=10ΩR_{eq}=2+3+5=10\Omega

MCQ No. 123

An electric iron draws 5 A from a 220 V supply. Its power rating is:

a. 550 W
b. 880 W
c. 1000 W
d. 1100 W

Correct answer: d. 1100 W

Explanation:

P=VI=220×5=1100WP=VI=220\times5=1100W

MCQ No. 124

A current of 4 A flows through a resistor for 15 minutes. The charge transferred is:

a. 1800 C
b. 2400 C
c. 3000 C
d. 3600 C

Correct answer: d. 3600 C

Explanation:

Q=It=4×900=3600CQ=It=4\times900=3600C

MCQ No. 125

A resistor connected across a 24 V supply carries 6 A current. The resistance is:

a. 2 Ω
b. 3 Ω
c. 4 Ω
d. 6 Ω

Correct answer: c. 4 Ω

Explanation:

R=VI=246=4ΩR=\frac{V}{I}=\frac{24}{6}=4\Omega

MCQ No. 126

A cell of emf 12 V and internal resistance 1 Ω supplies current to an external resistor of 5 Ω. The current in the circuit is:

a. 1 A
b. 2 A
c. 3 A
d. 4 A

Correct answer: b. 2 A

Explanation:
The total resistance is:

Rtotal=R+r=5+1=6ΩR_{\text{total}}=R+r=5+1=6\,\Omega

Using Ohm's law:

I=ER+r=126=2AI=\frac{E}{R+r}=\frac{12}{6}=2\,A

MCQ No. 127

A copper wire is stretched to twice its original length without changing its volume. The new resistance becomes:

a. RR

b. 2R2R

c. 4R4R

d. 8R8R

Correct answer: c. 4R4R

Explanation:
Since volume remains constant,

A=A2A'=\frac{A}{2}

Therefore,

R=ρ2LA/2=4RR'=\rho\frac{2L}{A/2}=4R

MCQ No. 128

The drift velocity of electrons is directly proportional to:

a. Cross-sectional area

b. Electric field

c. Resistivity

d. Resistance

Correct answer: b. Electric field

Explanation:
The drift velocity is given by

vd=μEv_d=\mu E

Hence it increases directly with the applied electric field.


MCQ No. 129

A battery delivers maximum power to an external circuit when:

a. External resistance is zero

b. External resistance is infinite

c. External resistance equals internal resistance

d. External resistance is twice the internal resistance

Correct answer: c. External resistance equals internal resistance

Explanation:
According to the Maximum Power Transfer Theorem,

R=rR=r

MCQ No. 130

The resistance of a wire increases by 20%. Assuming dimensions remain unchanged, its conductivity becomes approximately:

a. 20% greater

b. 16.7% smaller

c. 20% smaller

d. Unchanged

Correct answer: b. 16.7% smaller

Explanation:
Conductivity is inversely proportional to resistivity (and resistance for fixed dimensions).

σ=σ1.2=0.833σ\sigma'=\frac{\sigma}{1.2}=0.833\sigma

Hence conductivity decreases by about 16.7%.


MCQ No. 131

A voltmeter reads 11.6 V when connected across a cell of emf 12 V supplying a current of 2 A. The internal resistance of the cell is:

a. 0.1 Ω

b. 0.2 Ω

c. 0.3 Ω

d. 0.4 Ω

Correct answer: b. 0.2 Ω

Explanation:

E=V+IrE=V+Ir
12=11.6+2r12=11.6+2r
r=0.2Ωr=0.2\,\Omega

MCQ No. 132

Kirchhoff's Voltage Law is a direct consequence of conservation of:

a. Charge

b. Momentum

c. Energy

d. Mass

Correct answer: c. Energy

Explanation:
The algebraic sum of potential differences around any closed loop is zero because energy is conserved.


MCQ No. 133

A conductor has resistance 8 Ω at 20°C. If its temperature coefficient is 0.004 °C⁻¹, its resistance at 70°C is:

a. 8.8 Ω

b. 9.2 Ω

c. 9.6 Ω

d. 10 Ω

Correct answer: c. 9.6 Ω

Explanation:

R=R0(1+αΔT)R=R_0(1+\alpha\Delta T)
=8(1+0.004×50)=8(1+0.004\times50)
=8(1.2)=9.6Ω=8(1.2)=9.6\,\Omega

MCQ No. 134

Which device is most suitable for accurately measuring the emf of a cell?

a. Ammeter

b. Voltmeter

c. Potentiometer

d. Wheatstone bridge

Correct answer: c. Potentiometer

Explanation:
A potentiometer measures emf without drawing current from the source.


MCQ No. 135

The SI unit of electrical conductivity is:

a. Ω·m

b. Ω⁻¹

c. S m⁻¹

d. S

Correct answer: c. S m⁻¹

Explanation:
Conductivity is measured in Siemens per metre (S m⁻¹).


MCQ No. 136

A current of 3 A flows through a 6 Ω resistor for 5 minutes. The electrical energy dissipated is:

a. 8100 J

b. 10800 J

c. 16200 J

d. 32400 J

Correct answer: c. 16200 J

Explanation:

H=I2RtH=I^2Rt
=(3)2(6)(300)=(3)^2(6)(300)
=16200J=16200\,J

MCQ No. 137

A resistor obeys Ohm's law only when:

a. Temperature remains constant

b. Voltage is very high

c. Current is zero

d. Resistance is infinite

Correct answer: a. Temperature remains constant

Explanation:
Ohm's law is valid only if physical conditions, especially temperature, remain constant.


MCQ No. 138

The balancing condition for a Wheatstone bridge is:

a. R1+R2=R3+R4R_1+R_2=R_3+R_4

b. R1R2=R3R4R_1R_2=R_3R_4

c. R1R2=R3R4\frac{R_1}{R_2}=\frac{R_3}{R_4}

d. R1=R2=R3=R4R_1=R_2=R_3=R_4

Correct answer: c.

Explanation:
A Wheatstone bridge is balanced when the ratio of resistances in one arm equals that in the other arm.


MCQ No. 139

The resistance of a metallic conductor mainly arises due to collisions between electrons and:

a. Atomic nuclei

b. Lattice ions

c. Protons

d. Neutrons

Correct answer: b. Lattice ions

Explanation:
Free electrons collide with vibrating lattice ions, producing electrical resistance.


MCQ No. 140

A wire has resistance 12 Ω. If its diameter is doubled while keeping the length unchanged, the new resistance becomes:

a. 12 Ω

b. 6 Ω

c. 3 Ω

d. 1.5 Ω

Correct answer: c. 3 Ω

Explanation:

Area becomes four times.

R=R4=3ΩR'=\frac{R}{4}=3\,\Omega

MCQ No. 141

Which instrument is based on the null-deflection method?

a. Ammeter

b. Voltmeter

c. Potentiometer

d. Ohmmeter

Correct answer: c. Potentiometer

Explanation:
A potentiometer uses the null method, making it highly accurate.


MCQ No. 142

The power consumed by a resistor is maximum when expressed as:

a. P=VIP=\frac{V}{I}

b. P=VIP=VI

c. P=I/RP=I/R

d. P=V/RP=V/R

Correct answer: b. P=VIP=VI

Explanation:
Electrical power is

P=VIP=VI

Equivalent forms include I2RI^2R and V2/RV^2/R.


MCQ No. 143

A semiconductor generally has:

a. Positive temperature coefficient

b. Negative temperature coefficient

c. Zero temperature coefficient

d. Infinite resistance

Correct answer: b. Negative temperature coefficient

Explanation:
As temperature increases, more charge carriers become available, reducing resistance.


MCQ No. 144

Two resistors of 4 Ω and 12 Ω are connected in parallel. Their equivalent resistance is:

a. 2 Ω

b. 3 Ω

c. 6 Ω

d. 8 Ω

Correct answer: b. 3 Ω

Explanation:

R=4×124+12=3ΩR=\frac{4\times12}{4+12}=3\,\Omega

MCQ No. 145

The SI unit of electromotive force is:

a. Joule

b. Coulomb

c. Volt

d. Watt

Correct answer: c. Volt

Explanation:
EMF is measured in volts.


MCQ No. 146

The resistance of a conductor is independent of:

a. Length

b. Area

c. Material

d. Applied voltage (within Ohmic limit)

Correct answer: d. Applied voltage (within Ohmic limit)

Explanation:
For an ohmic conductor at constant temperature, resistance remains constant regardless of applied voltage.


MCQ No. 147

Which quantity remains constant in a series circuit?

a. Voltage

b. Current

c. Resistance

d. Power

Correct answer: b. Current

Explanation:
The same current passes through every component connected in series.


MCQ No. 148

A thermistor is most commonly used in:

a. Voltage amplification

b. Temperature sensing

c. Current multiplication

d. Magnetic shielding

Correct answer: b. Temperature sensing

Explanation:
Thermistors exhibit a large change in resistance with temperature.


MCQ No. 149

The resistance of an ideal ammeter is:

a. Infinite

b. Very high

c. Zero

d. 1 Ω

Correct answer: c. Zero

Explanation:
An ideal ammeter should not cause any voltage drop in the circuit.


MCQ No. 150

A source of emf has E = 9 V and r = 1 Ω. It is connected to a 17 Ω resistor. The terminal voltage is:

a. 8.0 V

b. 8.5 V

c. 9.0 V

d. 10.0 V

Correct answer: b. 8.5 V

Explanation:

Current,

I=917+1=0.5AI=\frac{9}{17+1}=0.5\,A

Terminal voltage,

V=EIr=9(0.5)(1)=8.5VV=E-Ir=9-(0.5)(1)=8.5\,V

MCQ No. 151

A current of 4 A flows through a conductor for 15 minutes. The total charge passing through the conductor is:

a. 900 C
b. 1800 C
c. 3600 C
d. 2400 C

Correct answer: c. 3600 C

Explanation:

Q=It=4×(15×60)=3600CQ=It=4\times(15\times60)=3600\,C

MCQ No. 152

A copper wire and a nichrome wire have the same length and cross-sectional area. The nichrome wire has a greater resistance because it has:

a. Greater conductivity

b. Greater resistivity

c. Smaller diameter

d. Larger area

Correct answer: b. Greater resistivity

Explanation:
Resistance depends directly on resistivity:

R=ρLAR=\rho\frac{L}{A}

Nichrome has much higher resistivity than copper.


MCQ No. 153

The current through a 24 Ω resistor connected across 120 V is:

a. 2 A

b. 4 A

c. 5 A

d. 6 A

Correct answer: c. 5 A

Explanation:
Using Ohm's law,

I=VR=12024=5AI=\frac{V}{R}=\frac{120}{24}=5A

MCQ No. 154

Two resistors of 6 Ω and 3 Ω are connected in series across a 9 V battery. The current in the circuit is:

a. 0.5 A

b. 1 A

c. 2 A

d. 3 A

Correct answer: b. 1 A

Explanation:

R=6+3=9ΩR=6+3=9\Omega
I=99=1AI=\frac{9}{9}=1A

MCQ No. 155

The current density in a conductor is directly proportional to:

a. Length

b. Electric field

c. Resistance

d. Cross-sectional area

Correct answer: b. Electric field

Explanation:
Microscopic Ohm's law:

J=σEJ=\sigma E

Current density increases with electric field.


MCQ No. 156

A 100 W, 220 V electric bulb draws a current of approximately:

a. 0.22 A

b. 0.45 A

c. 1.0 A

d. 2.2 A

Correct answer: b. 0.45 A

Explanation:

I=PV=100220=0.455AI=\frac{P}{V}=\frac{100}{220}=0.455A

MCQ No. 157

A cell has an emf of 2 V and an internal resistance of 0.5 Ω. When connected to a 3.5 Ω resistor, the terminal voltage is:

a. 1.50 V

b. 1.75 V

c. 2.00 V

d. 2.25 V

Correct answer: b. 1.75 V

Explanation:

I=23.5+0.5=0.5AI=\frac{2}{3.5+0.5}=0.5A
V=EIr=2(0.5)(0.5)=1.75VV=E-Ir=2-(0.5)(0.5)=1.75V

MCQ No. 158

The reciprocal of conductivity is:

a. Conductance

b. Resistance

c. Resistivity

d. Current density

Correct answer: c. Resistivity

Explanation:

ρ=1σ\rho=\frac{1}{\sigma}

MCQ No. 159

If the electric field inside a conductor becomes zero, the drift velocity of electrons becomes:

a. Infinite

b. Constant

c. Zero

d. Maximum

Correct answer: c. Zero

Explanation:
Since

vdEv_d\propto E

zero electric field means zero drift velocity.


MCQ No. 160

Which circuit element converts electrical energy directly into heat?

a. Capacitor

b. Resistor

c. Inductor

d. Transformer

Correct answer: b. Resistor

Explanation:
Electrical energy is converted into heat according to Joule's law.


MCQ No. 161

The resistance of a conductor becomes three times its original value. Assuming dimensions remain unchanged, its conductivity becomes:

a. Three times

b. One-third

c. Nine times

d. Unchanged

Correct answer: b. One-third

Explanation:
Conductivity is inversely proportional to resistance for a conductor of fixed dimensions.


MCQ No. 162

The equivalent resistance of 2 Ω, 3 Ω, and 6 Ω connected in parallel is:

a. 1 Ω

b. 2 Ω

c. 3 Ω

d. 6 Ω

Correct answer: a. 1 Ω

Explanation:

1R=12+13+16=1\frac1R=\frac12+\frac13+\frac16=1

Therefore,

R=1ΩR=1\Omega

MCQ No. 163

Kirchhoff's Current Law states that the algebraic sum of currents at a junction is:

a. One

b. Infinite

c. Zero

d. Equal to resistance

Correct answer: c. Zero

Explanation:
The total current entering a junction equals the total current leaving it.


MCQ No. 164

A 10 Ω resistor carries 3 A current. The power dissipated is:

a. 30 W

b. 60 W

c. 90 W

d. 120 W

Correct answer: c. 90 W

Explanation:

P=I2R=32×10=90WP=I^2R=3^2\times10=90W

MCQ No. 165

The balancing length in a potentiometer decreases when:

a. EMF increases

b. Potential gradient increases

c. Wire length increases

d. Current decreases

Correct answer: b. Potential gradient increases

Explanation:

E=kLE=kL

For constant emf,

L=EkL=\frac{E}{k}

Higher potential gradient gives smaller balancing length.


MCQ No. 166

The temperature coefficient of resistance for pure metals is generally:

a. Negative

b. Positive

c. Zero

d. Infinite

Correct answer: b. Positive

Explanation:
The resistance of metals increases with temperature.


MCQ No. 167

The resistance of a wire is 16 Ω. It is cut into four equal pieces. The resistance of each piece becomes:

a. 16 Ω

b. 8 Ω

c. 4 Ω

d. 2 Ω

Correct answer: c. 4 Ω

Explanation:
Resistance is proportional to length.

R=164=4ΩR=\frac{16}{4}=4\Omega

MCQ No. 168

The SI unit of current density is:

a. A

b. A m⁻¹

c. A m⁻²

d. C m⁻²

Correct answer: c. A m⁻²

Explanation:

J=IAJ=\frac{I}{A}

MCQ No. 169

An ideal source of emf should have:

a. Infinite internal resistance

b. Zero internal resistance

c. Infinite external resistance

d. Zero terminal voltage

Correct answer: b. Zero internal resistance

Explanation:
An ideal voltage source has no internal resistance.


MCQ No. 170

Which instrument is used to compare the emf of two cells accurately?

a. Ammeter

b. Potentiometer

c. Voltmeter

d. Galvanometer

Correct answer: b. Potentiometer

Explanation:
The potentiometer compares emf without drawing current.


MCQ No. 171

A conductor obeys Ohm's law if:

a. Current is constant

b. Resistance varies with voltage

c. Temperature remains constant

d. Voltage remains constant

Correct answer: c. Temperature remains constant

Explanation:
Ohm's law is valid only when physical conditions remain unchanged.


MCQ No. 172

A battery supplies 24 W to a resistor carrying 2 A. The resistance of the resistor is:

a. 3 Ω

b. 6 Ω

c. 12 Ω

d. 24 Ω

Correct answer: b. 6 Ω

Explanation:

P=I2RP=I^2R
24=4R24=4R
R=6ΩR=6\Omega

MCQ No. 173

A conductor has conductivity σ. If its resistivity becomes twice the original value, the conductivity becomes:

a. σ

b. 2σ

c. σ/2

d. 4σ

Correct answer: c. σ/2

Explanation:

σ=1ρ\sigma=\frac1\rho

MCQ No. 174

A potentiometer is preferred over a voltmeter because it:

a. Measures current

b. Draws no current from the source being measured

c. Has lower resistance

d. Measures resistance directly

Correct answer: b. Draws no current from the source being measured

Explanation:
The null-deflection method makes potentiometer measurements highly accurate.


MCQ No. 175

Three resistors of 6 Ω each are connected in parallel across a 12 V supply. The total current drawn from the source is:

a. 2 A

b. 4 A

c. 6 A

d. 8 A

Correct answer: c. 6 A

Explanation:

Equivalent resistance,

R=63=2ΩR=\frac{6}{3}=2\Omega

Therefore,

I=122=6AI=\frac{12}{2}=6A

MCQ No. 176

A resistor of 8 Ω is connected in parallel with a resistor of 24 Ω. The equivalent resistance is:

a. 4 Ω
b. 6 Ω
c. 8 Ω
d. 12 Ω

Correct answer: b. 6 Ω

Explanation:

For resistors in parallel,

1R=18+124=424=16\frac{1}{R}=\frac{1}{8}+\frac{1}{24}=\frac{4}{24}=\frac{1}{6}

Hence,

R=6ΩR=6\,\Omega

MCQ No. 177

A conductor has resistance 15 Ω at 20°C. If its temperature coefficient of resistance is 0.005 °C⁻¹, its resistance at 60°C will be:

a. 16 Ω

b. 17 Ω

c. 18 Ω

d. 20 Ω

Correct answer: c. 18 Ω

Explanation:

R=R0(1+αΔT)R=R_0(1+\alpha\Delta T)
R=15[1+(0.005)(40)]R=15[1+(0.005)(40)]
R=15(1.2)=18ΩR=15(1.2)=18\,\Omega

MCQ No. 178

The current through a 10 Ω resistor is 2 A. The potential difference across the resistor is:

a. 5 V

b. 10 V

c. 20 V

d. 40 V

Correct answer: c. 20 V

Explanation:

V=IR=(2)(10)=20VV=IR=(2)(10)=20\,V

MCQ No. 179

The balancing length of a potentiometer wire becomes half when:

a. Potential gradient becomes half

b. EMF becomes double

c. Potential gradient becomes double

d. Current becomes zero

Correct answer: c. Potential gradient becomes double

Explanation:

Since

L=EkL=\frac{E}{k}

doubling the potential gradient halves the balancing length.


MCQ No. 180

Two cells each of emf 2 V and internal resistance 1 Ω are connected in series with an external resistance of 6 Ω. The current is:

a. 0.4 A

b. 0.5 A

c. 1 A

d. 2 A

Correct answer: b. 0.5 A

Explanation:

Total emf

E=4VE=4V

Total resistance

R=6+2=8ΩR=6+2=8\Omega
I=48=0.5AI=\frac{4}{8}=0.5A

MCQ No. 181

A wire is stretched to three times its original length without changing its volume. Its resistance becomes:

a. 3R

b. 6R

c. 9R

d. 12R

Correct answer: c. 9R

Explanation:

Area becomes one-third.

R=ρ3LA/3=9RR'=\rho\frac{3L}{A/3}=9R

MCQ No. 182

The electric field inside an ideal conductor in electrostatic equilibrium is:

a. Infinite

b. Equal to applied field

c. Zero

d. Depends upon current

Correct answer: c. Zero

Explanation:
In electrostatic equilibrium, free charges rearrange until the electric field inside the conductor becomes zero.


MCQ No. 183

Which material is commonly used for making standard resistance coils because of its small temperature coefficient?

a. Copper

b. Aluminium

c. Manganin

d. Silver

Correct answer: c. Manganin

Explanation:
Manganin has a very low temperature coefficient and stable resistance.


MCQ No. 184

A 12 Ω resistor is connected across 24 V. The heat produced in 5 minutes is:

a. 720 J

b. 7200 J

c. 14400 J

d. 28800 J

Correct answer: c. 14400 J

Explanation:

Current,

I=2412=2AI=\frac{24}{12}=2A

Heat,

H=I2Rt=(2)2(12)(300)=14400JH=I^2Rt=(2)^2(12)(300)=14400J

MCQ No. 185

The resistance of a conductor depends upon:

a. Material only

b. Length only

c. Cross-sectional area only

d. Material, length, cross-sectional area and temperature

Correct answer: d. Material, length, cross-sectional area and temperature

Explanation:

Resistance is given by

R=ρLAR=\rho\frac{L}{A}

where resistivity depends upon temperature.


MCQ No. 186

The slope of the I–V graph for an ohmic conductor represents:

a. Resistance

b. Resistivity

c. Conductance

d. Power

Correct answer: c. Conductance

Explanation:

For an I–V graph,

Slope=IV=1R\text{Slope}=\frac{I}{V}=\frac{1}{R}

MCQ No. 187

A battery supplies 60 W at 12 V. The current supplied is:

a. 2 A

b. 3 A

c. 5 A

d. 6 A

Correct answer: c. 5 A

Explanation:

P=VIP=VI
I=6012=5AI=\frac{60}{12}=5A

MCQ No. 188

Which law is useful for solving complicated electrical networks?

a. Ohm's law

b. Coulomb's law

c. Kirchhoff's laws

d. Faraday's law

Correct answer: c. Kirchhoff's laws

Explanation:
Kirchhoff's laws are applied to analyze multi-loop and multi-branch circuits.


MCQ No. 189

The drift velocity of electrons depends upon:

a. Electric field only

b. Mobility of electrons only

c. Both electric field and mobility

d. Number of atoms only

Correct answer: c. Both electric field and mobility

Explanation:

vd=μEv_d=\mu E

where μ is mobility.


MCQ No. 190

The resistance of an ideal voltmeter is:

a. Zero

b. Very small

c. Infinite

d. One ohm

Correct answer: c. Infinite

Explanation:
An ideal voltmeter draws no current.


MCQ No. 191

Two resistors 3 Ω and 6 Ω are connected in parallel. The ratio of currents through them is:

a. 1 : 2

b. 2 : 1

c. 3 : 2

d. 1 : 3

Correct answer: b. 2 : 1

Explanation:
In parallel,

I1RI\propto\frac1R

Therefore,

I3Ω:I6Ω=2:1I_{3\Omega}:I_{6\Omega}=2:1

MCQ No. 192

The unit of mobility is:

a. m² V⁻¹ s⁻¹

b. Ω m

c. A m⁻²

d. V m⁻¹

Correct answer: a. m² V⁻¹ s⁻¹

Explanation:

Mobility is defined as

μ=vdE\mu=\frac{v_d}{E}

MCQ No. 193

The efficiency of a source is maximum when:

a. Internal resistance is zero

b. Load resistance equals internal resistance

c. Internal resistance exceeds load resistance

d. External resistance is zero

Correct answer: a. Internal resistance is zero

Explanation:
A source is most efficient when no power is wasted inside it.


MCQ No. 194

Which bridge circuit is commonly used for precise measurement of unknown resistance?

a. Maxwell bridge

b. Wheatstone bridge

c. Kelvin bridge

d. Schering bridge

Correct answer: b. Wheatstone bridge

Explanation:
The Wheatstone bridge measures resistance with high precision.


MCQ No. 195

A conductor has conductivity 5 × 10⁷ S m⁻¹. Its resistivity is:

a. 2×108Ωm2\times10^{-8}\,\Omega m

b. 5×108Ωm5\times10^{-8}\,\Omega m

c. 2×107Ωm2\times10^{-7}\,\Omega m

d. 5×107Ωm5\times10^{-7}\,\Omega m

Correct answer: a. 2×108Ω

Explanation:

ρ=1σ\rho=\frac1\sigma
=15×107=2×108Ωm=\frac1{5\times10^7}=2\times10^{-8}\Omega m

MCQ No. 196

The current through an ideal potentiometer during balancing is:

a. Maximum

b. Zero

c. Infinite

d. Equal to emf

Correct answer: b. Zero

Explanation:
At balance point no current flows through the galvanometer branch.


MCQ No. 197

The electrical power supplied to a resistor can be expressed as:

a. VIVI

b. I2RI^2R

c. V2R\frac{V^2}{R}

d. All of these

Correct answer: d. All of these

Explanation:
All three expressions are equivalent forms of electrical power.


MCQ No. 198

A resistance thermometer works on the principle that the resistance of a metal:

a. Decreases with temperature

b. Remains constant

c. Increases with temperature

d. Depends only on current

Correct answer: c. Increases with temperature

Explanation:
Pure metals have a positive temperature coefficient of resistance.


MCQ No. 199

Two identical cells connected in parallel have the same emf as one cell, but their effective internal resistance becomes:

a. Double

b. Four times

c. Half

d. Unchanged

Correct answer: c. Half

Explanation:
Connecting identical cells in parallel keeps the emf unchanged while reducing internal resistance to half.


MCQ No. 200

A potentiometer is more accurate than a voltmeter because it:

a. Has very low resistance

b. Measures current directly

c. Measures potential difference by the null method without drawing current

d. Uses Ohm's law instead of Kirchhoff's law

Correct answer: c. Measures potential difference by the null method without drawing current

Explanation:
Since a potentiometer uses the null-deflection method, it draws virtually no current from the source being measured. This eliminates loading effects and provides much greater accuracy than an ordinary voltmeter.


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